MISRA.COMMA

Comma operator is used.

MISRA C 2012 Rule 12.3: The comma operator should not be used.

Use of the comma operator is generally detrimental to the readability of code, and the same effect can be achieved by other means.

Category: Advisory

Analysis: Decidable, Single Translation Unit

Applies to: C90, C99

Rationale

Use of the comma operator is generally detrimental to the readability of code, and the same effect can usually be achieved by other means.

Example

f ( ( 1, 2 ), 3 ); /* Non-compliant - how many parameters? */

for ( i = 0, p = &a[ 0 ]; i < N; ++i, ++p )
{
}

MISRA-C 2004 Rule 12.10 (required): The comma operator shall not be used.

Use of the comma operator is generally detrimental to the readability of code, and the same effect can be achieved by other means.

MISRA-C++ 2008 Rule 5-18-1 (required): The comma operator shall not be used.

Rationale

Use of the comma operator is generally detrimental to the readability of code, and the same effect can be achieved by other means.

Example

f ( ( 1, 2 ), 3 ); // Non-compliant — how many parameters?